您所在位置：主题：这个错误的原因如何解决？
5ibc
[专家分：150] 发布于 2006-10-30 10:24:00
<?php
$db=mysql_connect("localhost","root","");
mysql_select_db("pUser",$db);
$result=mysql_query("select * from user where y_username='".$username."'",$db);
if($myrow=mysql_fetch_array($result))
{
echo("<script language='javascript'>alert('请用户名已经存在');history.back();</script>");
}
$result=mysql_query("insert into user(y_username,y_password) values('".$username."','".$password."')");
[color=FF0000]if($myrow=mysql_fetch_array($result))[/color]//错误行
{
echo("<script language='javascript'>alert('添加成功');window.location.href='loginadd.php';</script>");
}
?>
错误的原因:Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in loginaddnew.php on line 14
$db=mysql_connect("localhost","root","");
mysql_select_db("pUser",$db);
$result=mysql_query("select * from user where y_username='".$username."'",$db);
if($myrow=mysql_fetch_array($result))
{
echo("<script language='javascript'>alert('请用户名已经存在');history.back();</script>");
}
$result=mysql_query("insert into user(y_username,y_password) values('".$username."','".$password."')");
[color=FF0000]if($myrow=mysql_fetch_array($result))[/color]//错误行
{
echo("<script language='javascript'>alert('添加成功');window.location.href='loginadd.php';</script>");
}
?>
错误的原因:Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in loginaddnew.php on line 14
