#include "stdio.h"
#include "stdlib.h"

typedef int BOOL;
const int FALSE = 0;
const int TRUE = 1;

typedef struct list
{
    int data;
    struct list *next;
}list;

BOOL create(list *head)
{
    head=(list *)malloc(sizeof (list));
    if (head == NULL)
        return 0;
    head->data = -1;
    head->next = NULL;
    return 1;
}

BOOL add(list *l,int *data)
{
    list *temp,*a;
    a = l;
    temp = (list *)malloc(sizeof (list));
    if (temp==0)
        return FALSE;

    while (1)
    {
        
        if (a->next !=NULL)
            a= a->next;
        else break;
    }
    a->next = temp;
    temp->data = *data;
    temp->next = NULL;
    return TRUE;
}
void main ()
{
    list *a=NULL;

    int b[5]={1,2,3,4,5},i;
    create(a);

      for (i=0;i<=4;i++)
    {

         add(a,&b[i]);
        
    }


}

目的是实现建立空链表和在表尾处添加新结点。

问题是我的create函数出毛病了，以a为head指针建立不起来链表，错误类似形参，实参。。指针做为传递，应该不会出这个毛病吧。还是在malloc上有什么特殊的说法？高手指点一二，谢谢啦