这段代码实现的功能是将几个数从键盘输入(数的正负号和小数点加起来最长不超过20位），空格来分隔两数，按回车输入结束，输入第10个数后也结束．后面把这10个数字
输出．但是我输入一个数是正确的，输入两个以上的数的时候程序在输出完的数字后面有段乱码，查了半天也找不要原因，麻烦哪位高手运行下，帮我找找问题出在哪
data segment
       number   db 200 dup(?)
       numlenth dw 10 dup(?)
       count1    dw ?
       count2    dw ?  
       exit       db 0dh,0ah,'please any key to exit','$'
       input     db 'please input the numbers:(dapart them with keyboard "space" and end with keyboad "enter")',0dh,0ah,'$'
         output   db 0dh,0ah,'the sorted numbers are:',0dh,0ah,'$'
data ends 

code segment
                assume cs:code,ds:data
start:        mov ax,data
                mov ds,ax
                sub si,si
                sub bx,bx
                sub di,di
                sub cx,cx
                mov count1,0
                mov count2,0
                mov ah,09h
                lea dx,input
                int 21h 
                sub dx,dx
inputdata:mov ah,01h
                int 21h
                cmp al,20h
                jz nextdata
                cmp al,0dh
                jz endinput
                inc count1                                              
                mov number[si],al 
                inc si
                jmp inputdata                
nextdata: mov dx,count1
                mov numlenth[di],dx
                add count2,20 
                mov si,count2
                cmp count2,200
                jz sortdata
                mov count1,0
                add di,1
                jmp inputdata
endinput:mov dx,count1
               mov numlenth[di],dx
               inc di
sortdata: mov count1,0  
               mov ah,09h
               lea dx,output
                int 21h
                sub si,si                    
                 sub bx,bx
                 sub cx,cx
                 mov count1,0
                 mov count2,di
                  sub dx,dx
outputnext:mov cx,numlenth[si]
                 sub di,di
                 add di,count1
                 add cx,count1
outputdata:mov dl,number[di]
mov ah,02h
int 21h
inc di
cmp di,cx
jz outputspace
jmp outputdata

outputspace:
inc si
cmp si,count2
jz exitall
mov dl,20h
mov ah,02h
int 21h
add count1,20
jmp outputnext

exitall:
mov ah,09h 
lea dx,exit                                                              
int 21h
mov ah,01h
int 21h
mov ah,4ch
int 21h
code ends
end start