主题:递减数列
剑圣风暴
[专家分:450] 发布于 2007-07-23 08:28:00
递减数列,后一项为前一项减n
求出200以内5个递减的素数,且成等差数列。
以上程序怎么编?
回复列表 (共7个回复)
沙发
紫蝶公主 [专家分:30] 发布于 2007-07-23 08:55:00
CLS:DIM A(200):B(200)
FOR I=3 TO 200
F=-1
FOR J=2 TO I-1
IF I MOD J=0 THEN F=0:EXIT FOR
NEXT J
IF F=-1 THEN T=T+1:A(T)=I
NEXT I
FOR I=T TO 2 STEP -1
P=P+1
B(P)=A(I)-A(I-1)
NEXT I
FOR I=1 TO P-1
IF A(I)=A(I+1) THEN Y=Y+1 ELSE Y=0
IF Y=5 THEN PRINT A(T+1-I+4),A(T+1-I+3),A(T+1-I+2),A(T+1-I+1);A(T+1-I)
NEXT I
板凳
紫蝶公主 [专家分:30] 发布于 2007-07-23 09:19:00
怎么不加分???
3 楼
剑圣风暴 [专家分:450] 发布于 2007-07-23 11:48:00
tf
4 楼
剑圣风暴 [专家分:450] 发布于 2007-07-23 11:50:00
dd
5 楼
剑圣风暴 [专家分:450] 发布于 2007-07-23 11:52:00
ssada
6 楼
Matodied [专家分:7560] 发布于 2007-07-23 13:32:00
DECLARE FUNCTION isprime! (m!)
CLS
DIM a(5)
FOR i = 3 TO 193 STEP 2
FOR d = 2 TO (200 - i) \ 5
f = 1
FOR j = 1 TO 5
a(j) = i + d * (j - 1)
IF isprime(a(j)) = 0 THEN f = 0: EXIT FOR
NEXT j
IF f THEN GOSUB pri
NEXT d, i
END
pri: FOR i = 5 TO 1 STEP -1: PRINT a(i): NEXT i: END
FUNCTION isprime (m)
FOR i = 2 TO INT(SQR(m))
IF m MOD i = 0 THEN isprime = 0: EXIT FUNCTION
NEXT i
isprime = 1
END FUNCTION
7 楼
lml1996 [专家分:30] 发布于 2007-07-27 09:34:00
[size=5]CLS
X1=200
DO
X1=X1-1
K=INT(X1/4)
D=0
DO
D=D+1
S=0
FOR I=0 TO 4
X2=X1-I*D
GOSUB 100
S=S+P
NEXT I
IF S=5 THEN
FOR K=0 TO 4
PRINT X1-K*D;
NEXT K
PRINT
END IF
LOOP UNTIL S=5 OR D=K
LOOP UNTIL X1=1
END
100:P=1
FOR J=2 TO SQR(X2)
IF X2 MOD J=0 THEN P=0
NEXT J
RETURN
加分!
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