主题:谢谢编程
wangjieni11
[专家分:0] 发布于 2007-11-09 10:03:00
在二维数组中,找出一个元素在所在行上是最大的,所在列上最小的(注:可以不止一个,可能一个也没有)
回复列表 (共3个回复)
沙发
QB小猪 [专家分:1200] 发布于 2007-11-09 18:35:00
就是鞍点嘛...............
CLS
INPUT M, N
DIM A(M, N)
FOR I = 1 TO M
FOR J = 1 TO N: INPUT A(I, J): NEXT J: PRINT
NEXT I: CLS
FOR I = 1 TO M
FOR J = 1 TO N: PRINT USING "####"; A(j,i); : NEXT J
NEXT I: PRINT
FOR I = 1 TO M
AD = A(1,IF)
FOR J = 1 TO N
IF A(I, J) < AD THEN AD = A(I, J): L = I
NEXT J: H = I
FOR J = 1 TO M
IF A(J, L) < A(I, L) THEN 10
NEXT J: PRINT "鞍点:"; A(I, L)
10 NEXT I
END
锻炼一下你,有四处错误,自己找出来,加30分.........
板凳
蓝色的水晶 [专家分:90] 发布于 2007-11-14 15:33:00
在二维数组中,找出一个元素在所在行上是最大的,所在列上最小的(注:可以不止一个,可能一个也没有)
input m,n
dim a(m,n)
for i=1 to m
for j=1 to n
input a(i,j)
next j
next i
for i=1 to m
max=a(i,1)
for j=2 to n
if a(i,j)>max then max=a(i,j):I1=i:j1=j
next j
for k=1 to m
if a(k,j1)<max then goto hh:
next k
print max,i1,j1
p=p+1
hh:next i
if p=0 then print "没有鞍点"
end
3 楼
网虫一号 [专家分:1230] 发布于 2007-11-21 16:28:00
CLS
INPUT M, N
DIM A(M, N)
FOR I = 1 TO M
FOR J = 1 TO N: INPUT A(I, J): NEXT J: PRINT
NEXT I: CLS
FOR I = 1 TO M
FOR J = 1 TO N: PRINT USING "####"; A(j,i); : NEXT J
NEXT I: PRINT
FOR I = 1 TO M
AD = A(1,IF)
FOR J = 1 TO N
IF A(I, J) < AD THEN AD = A(I, J): L = I
NEXT J: H = I
FOR J = 1 TO M
IF A(J, L) < A(I, L) THEN 10
NEXT J: PRINT "鞍点:"; A(I, L)
10 NEXT I
END
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