主题:有谁帮我看看程序咯!递交时老是wrong answer
有谁帮我看看程序咯!
题目如下:
完美立方
Description
a^3 = b^3 + c^3 + d^3为完美立方等式。例如 12^3 = 6^3 + 8^3 + 10^3 。
对任意给定的正整数N(N<=100),寻找所有的四元组(a,b,c,d),使得a^3 = b^3 + c^3 + d^3,
其中 N>=a,b,c,d >1。
input
正整数N(N<=100),输入数据保证有解。输入以 0 结束。
Output
每行输出一个完美立方,按照a的值,从小到大依次输出。当两个完美立方等式中a的值相等时,则按照b值从小到大依次输出,依此类推。[即依次按照b、c、d进行非降升序排列输出,比较的优先级a>b>c>d].
输出形式为:
Cube = a, Triple = (b,c,d)
请参考sample.
Sample Input
24
Sample Output
Cube = 6, Triple = (3,4,5)
Cube = 12, Triple = (6,8,10)
Cube = 18, Triple = (2,12,16)
Cube = 18, Triple = (9,12,15)
Cube = 19, Triple = (3,10,18)
Cube = 20, Triple = (7,14,17)
Cube = 24, Triple = (12,16,20)
我的程序如下:
#include<iostream>
using namespace std;
int main(){
int N;
while(cin>>N&&N!=0){
int a=0,b=0,c=0,d=0;
for(int a=6;a<=N;a++)
for(int b=2;b<=N/2;b++){
for(int c=b;c<=N;c++)
for(int d=c;d<=N;d++){
if(a*a*a==b*b*b+c*c*c+d*d*d){
cout<<"Cube = "<<a<<",";
cout<<" Triple = "<<"("<<b<<","<<c<<","<<d<<")"<<endl;
break;
}
}
}
}
return 0;
}
到底是哪里错了啊???
题目如下:
完美立方
Description
a^3 = b^3 + c^3 + d^3为完美立方等式。例如 12^3 = 6^3 + 8^3 + 10^3 。
对任意给定的正整数N(N<=100),寻找所有的四元组(a,b,c,d),使得a^3 = b^3 + c^3 + d^3,
其中 N>=a,b,c,d >1。
input
正整数N(N<=100),输入数据保证有解。输入以 0 结束。
Output
每行输出一个完美立方,按照a的值,从小到大依次输出。当两个完美立方等式中a的值相等时,则按照b值从小到大依次输出,依此类推。[即依次按照b、c、d进行非降升序排列输出,比较的优先级a>b>c>d].
输出形式为:
Cube = a, Triple = (b,c,d)
请参考sample.
Sample Input
24
Sample Output
Cube = 6, Triple = (3,4,5)
Cube = 12, Triple = (6,8,10)
Cube = 18, Triple = (2,12,16)
Cube = 18, Triple = (9,12,15)
Cube = 19, Triple = (3,10,18)
Cube = 20, Triple = (7,14,17)
Cube = 24, Triple = (12,16,20)
我的程序如下:
#include<iostream>
using namespace std;
int main(){
int N;
while(cin>>N&&N!=0){
int a=0,b=0,c=0,d=0;
for(int a=6;a<=N;a++)
for(int b=2;b<=N/2;b++){
for(int c=b;c<=N;c++)
for(int d=c;d<=N;d++){
if(a*a*a==b*b*b+c*c*c+d*d*d){
cout<<"Cube = "<<a<<",";
cout<<" Triple = "<<"("<<b<<","<<c<<","<<d<<")"<<endl;
break;
}
}
}
}
return 0;
}
到底是哪里错了啊???