气泡法比较10个数的大小。程序如下
   

#include <stdio.h>                                                  (1)
void main()                                                         (2)
{
  int[10];                                                          (3)
  inti,j,t;                                                         (4)
  printf("please input 10 numbers\n");                              (5)
   for(i=0;i<10;i++)                                                (6)
      scanf("%d",a[i]);                                             (7)
      printf("\n");                                                 (8)
    for(j=0;j<9;j++)                                                (9)
      for(i=0;i<9-j;i++)                                            (10)
        if(a[i]>a[i+1])                                             (11)
          {
            t=a[i];                                                 (12)
             a[i]=a[i+1];                                           (13)
             a[i+1]=t;                                              (14)
           }
        printf("the sorted number \n");                             (15)
    for(i=0;i<10;i++)                                               (16)
        printf("%d",a[i]);                                          (17)
    printf("\n");                                                   (18)
}






(5)(6)(7)行初始化这个a[10]这个数组，是怎么实现的？？？
（12）（13）（14）比较两个数的大小，并交换。
谁在给解释一下（9）（10）（11）（16）（17）有什么作用。这个程序到底是怎么实现把十个数全部比较的呀？？谁在给个其他的例子