该程序是查找相同四码并替换原来的数组，如何让该程序在查找到第一个相同四码替换输出后就不在继续向下对比?谢谢赐教！
#include<stdio.h>
void main() 
{           
int i,j,s,AA,OKKO;
int a[14][5]={
                {3,5,6,11,18},
                {2,5,6,11,18},
                {1,5,8,11,13},
                {2,4,6,11,18},
                {1,3,6,11,18},
                {4,6,8,10,18},
                {2,4,7,10,18},
                {3,4,5,10,18},
                {2,4,5,10,18},
                {1,4,5,10,18},
                {2,3,5,10,18},
                {1,2,5,10,18},
                {3,5,7,9,18},
                {1,3,6,9,22},
};
int b[14][5]={
                {1,3,6,9,18},
                {6,7,9,11,12},
                {4,7,9,11,12},
                {2,7,9,11,12},
                {1,7,9,11,12},
                {3,7,8,11,12},
                {2,5,8,11,12},
                {1,5,8,11,12},
                {2,4,6,11,12},
                {1,3,6,11,12},
                {1,5,9,11,13},
                {3,6,8,10,12},
                {3,6,8,10,11},
                {3,6,8,9,13},
                };
   for(i=0;i<14;i++)                    
    {
        for(s=0;s<14;s++)
        {
              AA=0;
            for(j=0;j<5;j++)
            {                        
            if(b[s][j]==a[j])//a数组和b数组对比
                AA++;           //有相同的就记数
                if(AA>=4)
                {
                   for(j=0;j<5;j++)
                    a[j]=b[s][j];//数组中有等于大于四个数码的将b数组的码全部赋予a数组 
                   goto loop;
                }  
            }
        } 
loop:
        {
          for(j=0;j<5;j++)
              printf("%4d",a[j]);
            printf("\n");
            OKKO++;
        }
   }
}