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主题:(转贴)公历转农历源代码

前段时间做软件写了个公历转农历的函数,目前公开给大家参考,有兴趣的朋友可以在此基础上进一步完善其功能

/*------------农历转换函数-----------*/
char *GetDayOf(PSYSTEMTIME pSt)
{
/*天干名称*/
const char *cTianGan[] = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"};
/*地支名称*/
const char *cDiZhi[] = {"子","丑","寅","卯","辰","巳","午",
       "未","申","酉","戌","亥"};
/*属相名称*/
const char *cShuXiang[] = {"鼠","牛","虎","兔","龙","蛇",
       "马","羊","猴","鸡","狗","猪"};
/*农历日期名*/
const char *cDayName[] = {"*","初一","初二","初三","初四","初五",
       "初六","初七","初八","初九","初十",
       "十一","十二","十三","十四","十五",
       "十六","十七","十八","十九","二十",
       "廿一","廿二","廿三","廿四","廿五",       
       "廿六","廿七","廿八","廿九","三十"};
/*农历月份名*/
const char *cMonName[] = {"*","正","二","三","四","五","六",
       "七","八","九","十","十一","腊"};

/*公历每月前面的天数*/
const int wMonthAdd[12] = {0,31,59,90,120,151,181,212,243,273,304,334};
/*农历数据*/
const int wNongliData[100] = {2635,333387,1701,1748,267701,694,2391,133423,1175,396438
       ,3402,3749,331177,1453,694,201326,2350,465197,3221,3402
       ,400202,2901,1386,267611,605,2349,137515,2709,464533,1738
       ,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762
       ,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413
       ,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395
       ,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031
       ,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222
       ,268949,3402,3493,133973,1386,464219,605,2349,334123,2709
       ,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877};
static int wCurYear,wCurMonth,wCurDay;
static int nTheDate,nIsEnd,m,k,n,i,nBit;
TCHAR szNongli[30], szNongliDay[10],szShuXiang[10];
/*---取当前公历年、月、日---*/
wCurYear = pSt->wYear;
wCurMonth = pSt->wMonth;
wCurDay = pSt->wDay;
/*---计算到初始时间1921年2月8日的天数:1921-2-8(正月初一)---*/
nTheDate = (wCurYear - 1921) * 365 + (wCurYear - 1921) / 4 + wCurDay + wMonthAdd[wCurMonth - 1] - 38;
if((!(wCurYear % 4)) && (wCurMonth > 2))
  nTheDate = nTheDate + 1;

/*--计算农历天干、地支、月、日---*/
nIsEnd = 0;
m = 0;
while(nIsEnd != 1)
{
  if(wNongliData[m] < 4095)
   k = 11;
  else
   k = 12;
  n = k;
  while(n>=0)
  {
   //获取wNongliData(m)的第n个二进制位的值
   nBit = wNongliData[m];
   for(i=1;i<n+1;i++)
    nBit = nBit/2;

   nBit = nBit % 2;

   if (nTheDate <= (29 + nBit))
   {
    nIsEnd = 1;
    break;
   }

   nTheDate = nTheDate - 29 - nBit;
   n = n - 1;
  }
  if(nIsEnd)
   break;
  m = m + 1;
}
wCurYear = 1921 + m;
wCurMonth = k - n + 1;
wCurDay = nTheDate;
if (k == 12)
{
  if (wCurMonth == wNongliData[m] / 65536 + 1)
   wCurMonth = 1 - wCurMonth;
  else if (wCurMonth > wNongliData[m] / 65536 + 1)
   wCurMonth = wCurMonth - 1;
}

/*--生成农历天干、地支、属相 ==> wNongli--*/
wsprintf(szShuXiang,"%s",cShuXiang[((wCurYear - 4) % 60) % 12]);
wsprintf(szNongli,"%s(%s%s)年",szShuXiang,cTianGan[((wCurYear - 4) % 60) % 10],cDiZhi[((wCurYear - 4) % 60) % 12]);

/*--生成农历月、日 ==> wNongliDay--*/
if (wCurMonth < 1)
  wsprintf(szNongliDay,"闰%s",cMonName[-1 * wCurMonth]);
else
  strcpy(szNongliDay,cMonName[wCurMonth]);

strcat(szNongliDay,"月");
strcat(szNongliDay,cDayName[wCurDay]);
return strcat(szNongli,szNongliDay);

}

回复列表 (共4个回复)

沙发

呵呵
不错

板凳

太好了!
前一段时间我用VB编一个电子台历,在网上下载了一个公农历转换控件,可是时间只能能在1900~2050年之间,因此觉得功能受到限制。现在若用此算法改为VB版,就无此限制了。
请问如何用VC++将此算法转为控件?
                                              初学者

3 楼

我改了一下,可以運行,不過有些小bug
1 如果要轉換8000年的公曆為農曆,就會出錯
2 如果輸入錯誤的月份或者日期就會出錯

對輸入該函數的參數進行判斷,把判斷的年限限定,當然可以搞定。
不知道你的結構
    /*農曆資料*/
    const int wNongliData[100] =     
                 {2635,333387,1701,1748,267701,694,2391,133423,1175,396438
        ,3402,3749,331177,1453,694,201326,2350,465197,3221,3402
        ,400202,2901,1386,267611,605,2349,137515,2709,464533,1738
        ,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762
        ,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413
        ,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395
        ,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031
        ,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222
        ,268949,3402,3493,133973,1386,464219,605,2349,334123,2709
            ,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877};
在程序中有什麽用?它對算出農曆有什麽用?
看你的代碼和編程的風格知道是一位成熟的程序員!
謝謝你的源代碼!

4 楼

const int wMonthAdd[12] = {0,31,59,90,120,151,181,212,243,273,304,334};
    /*农历数据*/
    const int wNongliData[100] = {2635,333387,1701,1748,267701,694,2391,133423,1175,396438
        ,3402,3749,331177,1453,694,201326,2350,465197,3221,3402
        ,400202,2901,1386,267611,605,2349,137515,2709,464533,1738
        ,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762
        ,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413
        ,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395
        ,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031
        ,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222
        ,268949,3402,3493,133973,1386,464219,605,2349,334123,2709
        ,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877}

   小弟一直搞不懂上面这些数字是怎末得来的,有甚末规律吗?
   我现在需要把时间扩展一下,从1900到2099.
   有点急,谢谢.

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