主题:数字转换成汉字
wlp108696
[专家分:0] 发布于 2012-04-20 00:24:00
求助啊!
输入一个阿拉伯数字,输出为相应的汉字。例如输入389,输出为三百八十九,例如输入89203,输出八万九千二百零三
用C语言编写,并且有注释!
我在这先谢谢大家了!
沙发
lisy [专家分:390] 发布于 2012-04-22 00:21:00
#include <stdio.h>
#include <string.h>
char hznum[100];
char hzunit[15][3]={"","十","百","千","万","十","百","千","亿","十","百","千","万","十","百"};
char hzdigit[10][3]={"零","一","二","三","四","五","六","七","八","九"};
char numstr[20];
char *ReadNumByHZ(double v) {
char *p,*d;
int u,i;
sprintf(numstr,"%.15lg",v);
printf("%s\n",numstr);
if ('-'==numstr[0]) {
sprintf(hznum,"不支持读负数");
return hznum;
}
p=strchr(numstr,'e');
if (NULL!=p) {
sprintf(hznum,"不支持读太大或太小的数");
return hznum;
}
d=NULL;
p=strchr(numstr,'.');
if (NULL!=p) {
p[0]=0;
d=p+1;
}
u=strlen(numstr);
hznum[0]=0;
for (i=0;i<u;i++) {
if ('0'==numstr[i] && 0!=((u-1-i)%4)) {
sprintf(hznum,"%s%s",hznum,hzdigit[numstr[i]-'0']);
} else {
sprintf(hznum,"%s%s%s",hznum,hzdigit[numstr[i]-'0'],hzunit[u-1-i]);
}
}
//printf("%s\n",hznum);
u=strlen(hznum);
for (i=0;i<u;i+=2) {
if (0==strncmp(hznum+i,"零零",4)) {//多个连续的“零”改成一个“零”
memmove(hznum+i,hznum+i+2,u-i-2+1);
i-=2;
u-=2;
}
}
//printf("%s\n",hznum);
if (0==strcmp(hznum+u-2,"零")) hznum[u-2]=0;//末尾“零”去掉
//printf("%s\n",hznum);
u=strlen(hznum);
for (i=0;i<u;i+=2) {
if (0==strncmp(hznum+i,"零万",4) || 0==strncmp(hznum+i,"零亿",4)) {//“万”“亿”前是“零”去掉
memmove(hznum+i,hznum+i+2,u-i-2+1);
u-=2;
}
}
//printf("%s\n",hznum);
if (NULL!=d) {
sprintf(hznum,"%s点",hznum);
i=0;
while (1) {
if (0==d[i]) break;
sprintf(hznum,"%s%s",hznum,hzdigit[d[i]-'0']);
i++;
}
}
//printf("%s\n",hznum);
return hznum;
}
void main() {
printf("\n%s\n",ReadNumByHZ(130040600090.012));
}