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主题:经典c程序100例==81--90

经典c程序100例==81--90
【程序81】
题目:809*??=800*??+9*??+1 其中??代表的两位数,8*??的结果为两位数,9*??的结果为3位数。求??代表的两位数,及809*??后的结果。
1.程序分析:
2.程序源代码:
output(long b,long i)
{ printf("\n%ld/%ld=809*%ld+%ld",b,i,i,b%i);
}
main()
{long int a,b,i;
a=809;
for(i=10;i<100;i++)
{b=i*a+1;
if(b>=1000&&b<=10000&&8*i<100&&9*i>=100)
output(b,i); }
}
==============================================================
【程序82】
题目:八进制转换为十进制
1.程序分析:           
2.程序源代码:
main()
{ char *p,s[6];int n;
p=s;
gets(p);
n=0;
while(*(p)!='\0')
{n=n*8+*p-'0';
p++;}
printf("%d",n);
}
==============================================================
【程序83】
题目:求0—7所能组成的奇数个数。
1.程序分析:
2.程序源代码:
main()
{
long sum=4,s=4;
int j;
for(j=2;j<=8;j++)/*j is place of number*/
{ printf("\n%ld",sum);
if(j<=2)
s*=7;
else
s*=8;
sum+=s;}
printf("\nsum=%ld",sum);
}
==============================================================
【程序84】
题目:一个偶数总能表示为两个素数之和。
1.程序分析:
2.程序源代码:
#include "stdio.h"
#include "math.h"
main()
{ int a,b,c,d;
scanf("%d",&a);
for(b=3;b<=a/2;b+=2)
{ for(c=2;c<=sqrt(b);c++)
if(b%c==0) break;
if(c>sqrt(b))
d=a-b;
else
break;
for(c=2;c<=sqrt(d);c++)
if(d%c==0) break;
if(c>sqrt(d))
printf("%d=%d+%d\n",a,b,d);
}
}
==============================================================
【程序85】
题目:判断一个素数能被几个9整除
1.程序分析:
2.程序源代码:
main()
{ long int m9=9,sum=9;
int zi,n1=1,c9=1;
scanf("%d",&zi);
while(n1!=0)
{ if(!(sum%zi))
n1=0;
else
{m9=m9*10;
sum=sum+m9;
c9++;
}
}
printf("%ld,can be divided by %d \"9\"",sum,c9);
}
==============================================================
【程序86】
题目:两个字符串连接程序
1.程序分析:
2.程序源代码:
#include "stdio.h"
main()
{char a[]="acegikm";
char b[]="bdfhjlnpq";
char c[80],*p;
int i=0,j=0,k=0;
while(a[i]!='\0'&&b[j]!='\0')
{if (a[i] { c[k]=a[i];i++;}
else
c[k]=b[j++];
k++;
}
c[k]='\0';
if(a[i]=='\0')
p=b+j;
else
p=a+i;
strcat(c,p);
puts(c);
}
==============================================================
【程序87】
题目:回答结果(结构体变量传递)
1.程序分析:     
2.程序源代码:
#include "stdio.h"
struct student
{ int x;
char c;
} a;
main()
{a.x=3;
a.c='a';
f(a);
printf("%d,%c",a.x,a.c);
}
f(struct student b)
{
b.x=20;
b.c='y';
}
==============================================================
【程序88】
题目:读取7个数(1—50)的整数值,每读取一个值,程序打印出该值个数的*。
1.程序分析:
2.程序源代码:
main()
{int i,a,n=1;
while(n<=7)
{ do {
   scanf("%d",&a);
   }while(a<1||a>50);
for(i=1;i<=a;i++)
 printf("*");
printf("\n");
n++;}
getch();
}
==============================================================
【程序89】
题目:某个公司采用公用电话传递数据,数据是四位的整数,在传递过程中是加密的,加密规则如下:
   每位数字都加上5,然后用和除以10的余数代替该数字,再将第一位和第四位交换,第二位和第三位交换。
1.程序分析:
2.程序源代码:
main()
{int a,i,aa[4],t;
scanf("%d",&a);
aa[0]=a%10;
aa[1]=a%100/10;
aa[2]=a%1000/100;
aa[3]=a/1000;
for(i=0;i<=3;i++)
 {aa[i]+=5;
 aa[i]%=10;
 }
for(i=0;i<=3/2;i++)
 {t=aa[i];
 aa[i]=aa[3-i];
 aa[3-i]=t;
 }
for(i=3;i>=0;i--)
printf("%d",aa[i]);
}
==============================================================
【程序90】
题目:专升本一题,读结果。
1.程序分析:
2.程序源代码:
#include "stdio.h"
#define M 5
main()
{int a[M]={1,2,3,4,5};
int i,j,t;
i=0;j=M-1;
while(i {t=*(a+i);
*(a+i)=*(a+j);
*(a+j)=t;
i++;j--;
}
for(i=0;i printf("%d",*(a+i));
}

回复列表 (共3个回复)

沙发

[em2]我要进行C语言课程设计,我是题目是:学生成绩管理系统。你能帮我编一个吗?谢谢!
你的程序我一直都在关注着,这次就麻烦你帮我编应该吧!
   我的电子邮箱是:haijiaoshu@hotmail.com
  谢谢!

板凳

你可以到这个网站看看了啊
也是说学生成绩管理的程序
有一写源码
应该对你会有所帮助了
ttp://www.vczx.com/article/show.php?id=75

3 楼

#include <stdio.h>



typedef struct node
{
  int num;
  char name[20];
  char sex[10];
  int age;
  int english;
  int math;
  int computer;
  int zfen;
  struct node *next;
} Student;

Student* Initiate_Student();
Student* Create_Student(Student *head);
Student* Find_Student(Student *head, int num);
Student* Insert_Student(Student *head);
Student* Delete_Student(Student *head);
int ge=0;
float zhonfen[100];
float pinjunf[100];



int main (void)
{
  Student *head, *p;
  int choose, num;

  head = Initiate_Student();
  printf("%s\n%s\n",
  "#####################Student#######################",
  "__________________________________________________");
  head = Create_Student(head);
  while (1)
    {
      printf("%s\n%s\n%s\n%s\n%s\n%s\n%s",
      "1:see student   2:zhao xue sheng xu lie hao  3:xing ming zhao",
      "4:xue hao zhao   5:chai ru xue sheng xingxi 6:san chu xue sheng xingxi",
      "7:zhong feng yu ping jun feng 8:mei ge xue sheng feng shu",
      "9:zhong feng zui gao xue sheng xingxi 10:zhong feng zui di xue sheng xingxi",
      "11:ge feng su duan ren su",
      "0:exit",
      "please:");
      scanf("%d", &choose);

      switch (choose)
{
case 1:
   Print_Student(head);
   break;
case 2:
   printf("input xu lie hao:");
   scanf("%d", &num);
   p = Find_Student(head, num);
   printf("gai xue sheng xingxi:\n");
   printf("number\tnum\tname\tsex\tenglish-math-computer\tage\n");
   printf("(%d)\t%4d\t%s\t%s\t%d-%d-%d\t%2d\n\n", num, p -> num,
   p -> name, p -> sex,p -> english, p -> math,
                 p -> computer, p -> age);
   break;
case 3:
   LocateName_Student(head);
   break;
case 4:
   printf("input xu lie hao:");
   scanf("%d", &num);
   LocateNum_Student(head, num);
   break;
case 5:
   head = Insert_Student(head);
   break;
case 6:
   head = Delete_Student(head);
   break;
case 7:
   chengji(head);
   break;
case 8:
   zhongfen(head);
   break;
case 9:
   /*findmax(head);*/
   break;
case 10:
   /*findmin(head);*/
   break;
case 11:
   suxue(head);
   break;
  case 0:
   exit(0);
default:
   printf("\nSorry!\n");
}
    }

}

Student* Initiate_Student ()
{
  Student *head;
  head = (Student *) malloc (sizeof(Student));
  head -> next = NULL;
  return (head);
}

Student* Create_Student (Student *head)
{
  Student *new, *end;
  int age, num;
  int i,j=0;
  int english,math,computer;
  char input;
  int count;
  int choose, next = 1;
  end = head;

  while (next)
    {
      count = 0;
      new = (Student *) malloc (sizeof(Student));
      printf("input num:");
      scanf("%d", &num);
      getchar();
      printf("input name:");
      while ((input = getchar()) != '\n')
{
   new -> name[count] = input;
   count++;
}
      new -> name[count] = '\0';
      for(i=1;;i++)
     {printf("qing xuan ze(1:M 2:F):");
      scanf("%d", &choose);
      switch (choose)
{
case 1:
   strcpy (new -> sex, "M");
   j=0;
   break;
case 2:
   strcpy (new -> sex, "F");
   j=0;
   break;
default:
   printf("\nSorry please input!\n");
   j=1;
}
   if(j==0) break;
}
      printf("input age:");
      scanf("%d", &age);
      printf("input english:");
      scanf("%d", &english);
      printf("input math:");
      scanf("%d", &math);
      printf("input computer:");
      scanf("%d", &computer);
      ge=ge+1;
      zhonfen[ge]=english+math+computer;
      pinjunf[ge]=zhonfen[ge]/3;
      new -> num = num;
      new -> age = age;
      new -> english =english;
      new -> math = math;
      new -> computer = computer;
      new -> zfen = zhonfen[ge];
      end -> next = new;
      end = new;
      getchar();
      printf("ji xu input(Y/N)?");
      scanf("%c", &input);
      if (input == 'Y' || input == 'y')
next = 1;
      else
next = 0;
    }
  return (head);
}

int Print_Student (Student *head)
{
  Student *p;
  int j = 1;
  p = head;
  printf("xue sheng xing xi:\n\n");
  printf("number\tnum\tname\tsex\tenglish-math-computer\tage\n");
  printf("-----------------------------------------------------\n");
  if (head != NULL)
    {
      p = p -> next;
      while (p != NULL)
{
   printf("(%d)", j);
   j++;
printf("\t%4d\t%s\t%s\t%d-%d-%d\t%2d\n", p -> num, p -> name,
   p -> sex,p -> english, p -> math,
   p -> computer, p -> age);
   p = p -> next;
   if(j>ge) break;
}
    }
  printf("-----------------------------------------------------\n");
  printf("have  %d ge xue sheng.\n\n", j - 1);
  return;
}

Student* Find_Student (Student *head, int i)
{
  Student *p;
  int j = 0;
  p = head;
  while ((p -> next != NULL) && (j < i))
    {
      p = p -> next;
      j++;
    }
  if (i == j)
    return (p);
  else
    {
      printf("Sorry gai wei zi bu cheng zai!\n");
      return 0;
    }
}

Student* Insert_Student (Student *head)
{
  Student *p, *s;
  int i,j=0;
  int age, num;
  int english,math,computer;
  char input;
  int count;
  int choose, insertLocation;

  printf("input num:");
  scanf("%d", &insertLocation);
  p = Find_Student(head, insertLocation - 1);
  if (p == NULL)
    {
      printf("bu cheng zai  %d  ge wei zi!\n", insertLocation);
      return 0;
    }
  else
    {
      count = 0;
      s = (Student *) malloc (sizeof(Student));
      printf("input num:");
      scanf("%d", &num);
      getchar();
      printf("input name:");
      while ((input = getchar()) != '\n')
{
   s -> name[count] = input;
   count++;
}
      s -> name[count] = '\0';
      for(i=1;;i++)
      {printf("qing xuan ze(1:M 2:F):");
      scanf("%d", &choose);
      switch (choose)
{
case 1:
   strcpy (s -> sex, "M");
   j=0;
   break;
case 2:
   strcpy (s -> sex, "F");
   j=0;
   break;
default:
   printf("\nSorry please input!\n");
   j=1;
}
if(j==0) break;
}
      printf("input age:");
      scanf("%d", &age);
      printf("input english:");
      scanf("%d", &english);
      printf("input math:");
      scanf("%d", &math);
      printf("input computer:");
      scanf("%d", &computer);
      ge=ge+1;
      s -> num = num;
      s -> english = english;
      s -> math = math;
      s -> computer = computer;
      s -> age = age;
      s -> next = p -> next;
      p -> next = s;
    }
  return (head);
}

Student* Delete_Student (Student *head)
{
  Student *p, *s;
  int i;

  printf("input yao Delete num:");
  scanf("%d", &i);
  p = Find_Student(head, i - 1);
  if ((p != NULL) && (p -> next != NULL))
    {
      s = p -> next;
      p -> next = s -> next;
      free(s);
    }
  else
    {
      printf("bu cheng zai  %d ge !\n", i);
      return 0;
    }
    ge=ge-1;
  return (head);
}

int LocateName_Student (Student *head)
{
  Student *p;
  char input;
  char siName[20], diName[20];
  int count = 0, j = 0, num;
  p = head;


  getchar();
  printf("input zhao name:");
  while ((input = getchar()) != '\n')
    {
      siName[count] = input;
      count++;
    }
  siName[count] = '\0';

  while ((p -> next != NULL) && (strcmp(siName, p -> name) != 0))
  {
    p = p -> next;
    j++;
  }
  if (strcmp(siName, p -> name) == 0)
    {
      printf("xue sheng xingxi:\n");
      printf("number\tnum\tname\tsex\tenglish-math-computer\tage\n");
      printf("(%d)\t%4d\t%s\t%s\t%d-%d-%d\t%2d\n\n", j, p -> num,
      p -> name, p -> sex,p -> english, p -> math,
      p -> computer, p -> age);
    }
  else
    {
      printf("\nSorry!\n");
      return 0;
    }
}

int LocateNum_Student (Student *head, int i)
{
  Student *p;
  int j = 0;
  p = head;
  while ((p -> next != NULL) && (p -> num != i))
    {
      p = p -> next;
      j++;
    }
  if (p -> num == i)
    {
      printf("xue sheng xingxi:\n");
      printf("number\tnum\tname\tsex\tenglish-math-computer\tage\n");
      printf("(%d)\t%4d\t%s\t%s\t%d-%d-%d\t%2d\n\n", j, p -> num,
      p -> name, p -> sex,p -> english, p -> math,
      p -> computer, p -> age);
    }
  else
    {
      printf("\nSorry!\n");
      return 0;
    }
}



int chengji()
{/*Student *p;
p= (Student *) malloc (sizeof(Student));*/
int j;
for(j=1;j<4;j++)
    {
printf("zhong cheng ji wei:%f   pingjunfeng:%f\n",zhonfen[j],pinjunf[j]);
              }
}

int zhongfen()
{int j;
float kkk,pingjun,sss;
kkk=0;sss=0;
for(j=0;j<=ge;j++)
    {
     kkk=kkk+zhonfen[j];
     sss=sss+pinjunf[j];
}
pingjun=sss/ge;
printf("zhong cheng ji wei:%f   pingjunfeng:%f\n",kkk,pingjun);
}
/*
int findmax(Student *head)
{ struct student *p;
int i,temp=0;
float max;

for(max=head->zfen,i=1;i<ge;i++)
   if(head->zfen>max)
       {max=head->zfen;temp=i;}
p=head+temp;
printf("\nThe max mum zfen:\n");
printf("No: name: sex: age: english: math: computer: zfen:\n");
printf("%d %s %s %d %d %d %d %d",p->num,p->name,p->sex,p->age,p->english,p->math,p->computer);
}


int findmin(Student *head)
{
int i,temp=0;
float min;
for(min=head->zfen,i=1;i<15;i++)
   if(head->zfen<min)
       {min=head->zfen;temp=i;}
head=head+temp;
printf("\nThe min mum zfen:\n");
printf("No: name: sex: money: english: math: computer: zfen:\n");
printf("%d %s %s %d %d %d %d %d",head->num,head->name,head->sex,head->age,head->english,head->math,head->computer);
}
*/
int suxue(Student *head)
{int i,aaa,bbb,ccc,ddd,eee;
aaa=0;
bbb=0;
ccc=0;
ddd=0;
eee=0;
for(i=1;i<4;i++)
   {if(head->math>=90) aaa=aaa+1;
   if(head->math>=80 && head->math<90) bbb=bbb+1;
   if(head->math>=70 && head->math<80) ccc=ccc+1;
   if(head->math>=60 && head->math<70) ddd=ddd+1;
   if(head->math<60) eee=eee+1;}
printf("90 yi shang you %d",aaa);
printf("80--90 you %d",aaa);
printf("70--80 you %d",aaa);
printf("60--70 you %d",aaa);
printf("60 yi xia you %d",aaa);
}

int yiyu(Student *head)
{int i,aaa,bbb,ccc,ddd,eee;
aaa=0;
bbb=0;
ccc=0;
ddd=0;
eee=0;
for(i=1;i<4;i++)
   {if(head->english>=90) aaa=aaa+1;
   if(head->english>=80 && head->english<90) bbb=bbb+1;
   if(head->english>=70 && head->english<80) ccc=ccc+1;
   if(head->english>=60 && head->english<70) ddd=ddd+1;
   if(head->english<60) eee=eee+1;}
printf("90 yi shang you %d",aaa);
printf("80--90 you %d",aaa);
printf("70--80 you %d",aaa);
printf("60--70 you %d",aaa);
printf("60 yi xia you %d",aaa);
}

int jisuanji(Student *head)
{int i,aaa,bbb,ccc,ddd,eee;
aaa=0;
bbb=0;
ccc=0;
ddd=0;
eee=0;
for(i=1;i<4;i++)
   {if(head->computer>=90) aaa=aaa+1;
   if(head->computer>=80 && head->computer<90) bbb=bbb+1;
   if(head->computer>=70 && head->computer<80) ccc=ccc+1;
   if(head->computer>=60 && head->computer<70) ddd=ddd+1;
   if(head->computer<60) eee=eee+1;}
printf("90 yi shang you %d",aaa);
printf("80--90 you %d",aaa);
printf("70--80 you %d",aaa);
printf("60--70 you %d",aaa);
printf("60 yi xia you %d",aaa);
}



这是我编写的,但是时间问题还有两个功能没有实现,我这里运行是完全可以的

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