fortran读取数据到单元5就结束了,forrt1:severe(24):end-of-file during read,unit5,
我怀疑是读数据的问题,开头部分数据不能全读入,到单元5就终止了。
我输入,输出文件都有,但是输出文件只有部分输出
我把程序上传了,大神有时间给看看,万分感激
下面上图


http://image.keyan.cc/data/bcs/2015/0630/w145h3869417




http://image.keyan.cc/data/bcs/2015/0630/w146h3869417_1435648114_346.png

http://image.keyan.cc/data/bcs/2015/0630/w166h3869417_1435648129_349.png

http://image.keyan.cc/data/bcs/2015/0630/w110h3869417_1435648984_742.png


C----------FRAME.FOR---(FOR FRAME PROBLEMS)---------
	DIMENSION LOC(3,2),IFIX(5),AREA(3),FINT(3),CX(4),CY(4),
     1 F(12),FR(12),FE(3,6)
	COMMON NN,NE,ND,NFIX,E
C---------------------------------------------
	OPEN (5,FILE='F1.DAT',STATUS='OLD')
	OPEN (6,FILE='OUTF1.')
	READ(5,*)NN,NE,ND,NFIX,E
	WRITE(6,105) NN,NE,ND,NFIX,E
105	FORMAT(4X,'NN NE ND NFIX  E'/4I5,E11.4)
	READ(5,*) (LOC(I,1),LOC(I,2),AREA(I),FINT(I),I=1,NE)
	WRITE(6,108)
108	FORMAT(/1X,'ELEMENT NODE1 NODE2 AREA FINT')
	WRITE(6,110)(I,LOC(I,1),LOC(I,2),AREA(I),FINT(I),I=1,NE)
110	FORMAT(1X,3I6,2E12.4)
	READ(5,*)(CX(J),CY(J),J=1,NN)
	WRITE(6,112)
112	FORMAT(/4X,'NODE X-COORD Y-COORD')
	WRITE(6,115) (J,CX(J),CY(J),J=1,NN)
115	FORMAT(4X,I3,3X,2E12.4)
	READ(5,*)(IFIX(K),K=1,NFIX)
	WRITE(6,118)(IFIX(K),K=1,NFIX)
118	FORMAT(/3X,'IFIX=',6I4)
C--------------------------------------------------
      CALL CST (LOC,IFIX,AREA,FINT,CX,CY,F,FR,FE)
C---------------------------------------------------
	WRITE(6,130)
130	FORMAT(/4X,'NODE',5X,'X-DISP',8X,'Y-DISP',9X,'THITA')
	WRITE(6,135)(I,F(3*I-2),F(3*I-1),F(3*I),I=1,NN)
135	FORMAT(2X,I5,3E15.6)
	WRITE(6,140)
140	FORMAT(/4X,'REACTION NODAL FORCES FROM THE EQUATIONS',
     1 /4X,'NODE',5X,'X-LOAD',8X,'Y-LOAD',9X,'MOMENT')
	WRITE(6,145) (I,FR(3*I-2),FR(3*I-1),FR(3*I),I=1,NN)
145	FORMAT(2X,I5,3E15.6)
	WRITE(6,150)
150	FORMAT(/4X,'ELEMENT',4X,'AXI-F',7X,'SHEAR-Q',7X,'MOMENT-M')
	DO 10 I=1,NE
10	WRITE(6,155) I,FE(I,1),FE(I,2),FE(I,3),FE(I,4),FE(I,5),FE(I,6)
155	FORMAT(2X,I4,3E15.6/6X,3E15.6)
	STOP
	END
C----------------------------------------------------
	SUBROUTINE CST(LOC,IFIX,AREA,FINT,CX,CY,F,FR,FE)
	DIMENSION LOC(NE,2),IFIX(NFIX),AREA(NE),FINT(NE),CX(NN),CY(NN),
	1 F(ND),FR(ND),FE(NE,6),
	2 P1(3,6),P2(3,6),GK(12,12),GK1(12,12),AL(3),TT(3,6,6),BKL(3,6,6),
	3 T(6,6),CSS(3),SNN(3),EK(6,6),EKL(6,6),EKK(3,6,6),XX(6),BA(6,6)
	COMMON NN,NE,ND,NFIX,E
C-------------------------------------------------------
	DO 5 I=1,NE
	I1=LOC(I,1)
	I2=LOC(I,2)
	X12=CX(I2)-CX(I1)
	Y12=CY(I2)-CY(I1)
	AL(I)=SQRT(X12* *2+Y12* *2)
	CSS(I)=X12/AL(I)
	SNN(I)=Y12/AL(I)
5	CONTINUE
C	FOR CONCENTRAL FORCE,SET TO A NODE

       	READ (5,*) NP,NVD
	IF (NP.EQ.0) GO TO 15
	DO 10 II=1,NP
	READ (5,*) (I,F(3*I-2),F(3*I-1),F(3*I),I=2,4)


10	CONTINUE
15	CONTINUE
C	FOR VERTICAL DISTRIBUTED LOADING OF AN ELEMENT 
	IF(NVD.EQ.0) GO TO 25
	DO 20 II=1,NVD
	READ(5,*)IE,Q
	I1=LOC(IE,1)
	I2=LOC(IE,2)
	P1(IE,3*I1-1)=Q*AL(IE)/2.
	P1(IE,3*I1)=Q*AL(IE)* *2/12.
	P1(IE,3*I2-1)=Q*AL(IE)/2.
	P1(IE,3*I2)=-Q*AL(IE)* *2/12.
20	CONTINUE
25	CONTINUE
C----------------------------------------------------
	DO 30 I=1,ND
	DO 30 J=1,ND
30	GK(I,J)=0.0
C-----------------------------------------------
	DO 100 I=1,NE
	DO 35 J=1,6
	DO 35 K=1,6
	EKL(J,K)=0.0
	EK(J,K)=0.0
35	T(J,K)=0.0
C------------------------------------------------
	EAL=E*AREA(I)/AL(I)
	EIL1=E*FINT(I)/AL(I)
	EIL2=E*FINT(I)/AL(I)* *2
	EIL3=E*FINT(I)/AL(I)* *3
	EKL(1,1)=EAL
	EKL(2,2)=12.*EIL3
	EKL(3,3)= 4.*EIL1
	EKL(4,4)=EAL
	EKL(5,5)=12.*EIL3
	EKL(6,6)=4.*EIL1
	EKL(3,2)=6.*EIL2
	EKL(4,1)=-EAL
	EKL(5,2)=-12.*EIL3
	EKL(5,3)=-6.*EIL2
	EKL(6,2)=6.*EIL2
	EKL(6,3)=2.*EIL1
	EKL(6,5)=-6.*EIL2
	DO 50 II=1,5
	DO 50 JJ=II+1,6
50	EKL(II,JJ)=EKL(JJ,II)
	DO 55 K=1,6	
	DO 55 L=1,6
	EKK(I,K,L)=EKL(K,L)
C	WRITE (6,140) I,K L,EKL(K,L),EKK(I,K,L)
140	FORMAT(1X,'IKL,EK',3I4,2E12.5)
55	CONTINUE
	T(1,1)=CSS(I)
	T(1,2)=-SNN(I)
	T(2,1)=SNN(I)
	T(2,2)=CSS(I)
	T(3,3)=1.
	T(4,4)=CSS(I)
	T(4,5)=-SNN(I)
	T(5,4)=SNN(I)
	T(5,5)=CSS(I)
	T(6,6)=1.
C----------------------------------------------------
	DO 60 J=1,6
	DO 60 K=1,6
	TT(I,J,K)=T(J,K)
60	P2(I,J)=P2(I,J)+T(J,K)*P1(I,K)
C-------------------------------------------------------
	
	DO 65 II=1,6
	DO 65 J=1,6
	BA(II,J)=0.0
	DO 65 K=1,6
	BA(II,J)=BA(II,J)+TT(I,II,K)*EKL(K,J)
65	CONTINUE
	EK(II,J)=0.0  
	DO 70 II=1,6
	DO 70 J=1,6
	DO 70 K=1,6
	EK(II,J)=EK(II,J)+BA(II,K)*TT(I,J,K)
70	CONTINUE
C	WRITE(6,120) ((I,II,J,EK(II,J),TT(I,II,J),II=1,6),J=1,6)
120	FORMAT (1X,'I,II,J,EK,TT=',3I4,2E12.5)
C--------------------------------------------------------------
	DO 85 INODE=1,2
	NODEI=LOC(I,INODE)
	DO 85 IDOFN=1,3
	NROWS=(NODEI-1)*3+IDOFN
	NROWE=(INODE1-1)*3+IDOFN
	F(NROWS)=F(NROWS)+P2(I,NROWE)
	DO 85 JNODE=1,2
	NODEJ=LOC(I,JNODE)
	DO 85 JDOFN=1,3
	NCOLS=(NODEJ-1)*3+JDOFN
	NCOLE=(JNODE-1)*3+JDOFN
85	GK(NROWS,NCOLS)=GK(NROWS,NCOLS)+EK(NROWE,NCOLE)
100	CONTINUE 
	DO 88 I=1,ND
	DO 88 J=1,ND
88	GK1(I,J)=GK(I,J)
	WRITE(6,160)
160	FORMAT(/4X,'nodal forces from applied loads',
     1 /4X,'NODE',5X,'X-LOAD',8X,'Y-LOAD',9X,'MOMENT')
	WRITE (6,165) (I,F(3*I-2),F(3*I-1),F(3*I),I=1,NN) 
165	FORMAT(2X,I5,3E15.6)
C	WRITE(6,170)((I,J,GK(I,J),J=1,ND),I=1,ND)
170	FORMAT (1X,'I,J,GK1',2I4,E12.5,2X,2I4,E12.5)
C--------------------------------------------------------
	DO 90 I=1,NFIX
	IX=IFIX(I)
90	GK(IX,IX)=GK(IX,IX)*1.0E15
C-------------------------------------------------------------
	CALL GAUSS(GK,F,ND)
C--------------------------------------------------------------
	DO 92 I=1,ND
	FR(I)=0.0
	DO 94 J=1,ND
94	FR(I)=FR(I)+GK1(I,J)*F(J)
92	FR(I)=FR(I)-F(I)
C---------------------------------------------------------------
	DO 95 I=1,NE
	I1=LOC(I,1)
	I2=LOC(I,2)
	XX(1)=F(3*I1-2)
	XX(2)=F(3*I1-1)
	XX(3)=F(3*I1)
	XX(4)=F(3*I2-2)
	XX(5)=F(3*I2-1)
	XX(6)=F(3*I2)
	DO 96 J=1,6
	DO 96 K=1,6
	BKL(I,J,K)=0.0
	DO 96 L=1,6
	BKL(I,J,K)=BKL(I,J,K)+EKK(I,J,L)*TT(I,K,L)
96	CONTINUE
	DO 97 J=1,6
	FE(I,J)=0.0
	DO 97 K=1,6
	FE(I,J)=FE(I,J)+BKL(I,J,K)*XX(K)
97	CONTINUE 
      DO 98 J=1,6
98	FE(I,J)=FE(I,J)-P1(I,J)
95	CONTINUE
	RETURN
	END
C--------------------GAUSS'S METHOD----------------------
	SUBROUTINE GAUSS(A,B,N)
	DIMENSION A(N,N),B(N)
	DO 1 I=1,N
	I1=I+1
	DO 10 J=I1,N
10	A(I,J)=A(I,J)/A(I,I)
	B(I)=B(I)/A(I,I)
	A(I,I)=1.0
	DO 20 J=I1,N
	DO 30 M=I1,N
30	A(J,M)=A(J,M)-A(J,I)*A(I,M)
20	B(J)=B(J)-A(J,I)*B(I)
1	CONTINUE
	DO 40 I=N-1,1,-1
	DO 50 J=I+1,N
50	B(I)=B(I)-A(I,J)*B(J)
40	CONTINUE
	RETURN
	END 

http://image.keyan.cc/data/bcs/2015/0630/w149h3869417_1435649483_667.png