回 帖 发 新 帖 刷新版面

主题:类似三子连珠的game,用户直接输入回车时的问题, 代码如下

#include <stdio.h>
#include<string.h>
#include<stdlib.h>

void swap(char *player);
void change_ele1(int dev,int mod, char (*r)[12],char *player);
int if_end(char  (*row)[12]);
char *prompt();
void main()
{
char quit,map[4][12]={"---+---+---","-1-+-2-+-3-","-4-+-5-+-6-","-7-+-8-+-9-"};  //the original map
char row[3][12]={"   |   |   ","   |   |   ","   |   |   "};  
int turn=0,pos,dev,mod,if_num; //pos=postion, dev=devision,
char player[2]="X";
int  check_end=0,empty;
char *for_prompt;

  while(turn<=6 && check_end==0)   // game isn't over and need to add new element
  {
    turn=turn+1;
    printf("%s\n%s\n%s\n%s\n%s\n%s\n%s\n",map[0],row[0],map[1],row[1],map[2],row[2],map[3]);
      // print out map
    do
     {
           
           printf("player %s:",player);
           if_num=scanf("%d",&pos);
         if(if_num==0)           // user input isn't number!
          {
           for_prompt=prompt();
 
           if(strcmp(for_prompt,"Q")==0)      // user input "Q"  
            {
             swap(player);
             printf("player %s wins!\n",player);
             exit(EXIT_SUCCESS);
            }
           else if(for_prompt[0]=='\0')  //user input '/n'
            {
              printf("can't skip step!\n");
              empty=0;
            }
           else
            {
              printf("Invalid input!\n");
              empty=0;
            }
          }
         else if(pos>9 || pos<=0)    
          {
            printf("Invalid input!\n");
            empty=0;          
          }
         else    // input is number
          {

           dev=pos/3;
           mod=pos%3;              
                              
            if(mod==1)     // check the chosed postion is empty or not
             {
               if(row[dev][1]==' ')
                {
                  empty=1;
                }
               else
                {
                  empty=0;
                }
             }
            else if(mod==2)
             {
                if(row[dev][5]==' ')
                 {
                   empty=1;
                 }
              else
               {
                 empty=0;
               }
 
             }
            else
             {
                if(row[dev-1][9]==' ')
                 {
                   empty=1;
                 }
                else
                 {
                   empty=0;
                 }

             }
           }           
    }while(empty==0);  //repeat cheak for the input!
                 
    change_ele1(dev,mod,row,player); // use function to change new element                          
    check_end=if_end(row);       // if somebody wins
            
    if(check_end==1)  
     {
      printf("%s\n%s\n%s\n%s\n%s\n%s\n%s\n",map[0],row[0],map[1],row[1],map[2],row[2],map[3]);
      printf("1:player %s wins!\n",player);
      exit(EXIT_SUCCESS);
     }

    else     //no player wins
     {            
        swap(player);          
     }
 
 }// first while loop




while(turn>6 && check_end ==0)  // turn > 3
 {
    printf("do nothing!\n");
    // move from one to one until a player win~~~
 


    
 }

} //main loop









void swap(char *player)
{
if(player[0]=='X')
  {
   player[0]='O';
  }
else
  {
   player[0]='X';
  }

}



void change_ele1(int dev,int mod, char (*row)[12],char *player)
{   
        if(dev==0)
         {
            if(mod==1)
             {
               row[0][1]=player[0];  
               
             }
            else
             {
               row[0][5]=player[0];
             }

         }
       else if(dev==1)
         {
            if(mod==1)
             {
               row[1][1]=player[0];  
             }
            else if(mod==2)
             {
               row[1][5]=player[0];
             }
            else
             {
               row[0][9]=player[0];
             }

         }
       else  if(dev==2)
         {
            if(mod==1)
             {
               row[2][1]=player[0];  
             }
            else if(mod==2)
             {
               row[2][5]=player[0];
             }
            else
             {
               row[1][9]=player[0];
             }

         }   
       else
         {
            if(mod==0)
             {
               row[2][9]=player[0];  
             }                    
         }  
 

}





int if_end(char (*row)[12])
{
 if((row[0][1] != ' ')&&row[0][1] == row[0][5] && row[0][5]== row[0][9])
 {
  return 1;
 }
 
 else if((row[1][1] != ' ') && row[1][1] == row[1][5] && row[1][5] == row[1][9])
 {
  return 1;
 }

 else if((row[2][1] != ' ') && row[2][1] == row[2][5] && row[2][5] == row[2][9])
 {
  return 1;
 }                        // compaire every row



else if((row[0][1] != ' ') && row[0][1] == row[1][1] && row[1][1]== row[2][1])  
 {
return 1;
 }

else if((row[0][5] != ' ') && row[0][5] == row[1][5] && row[1][5]== row[2][5])  
 {
return 1;
 }

 
else if((row[0][9] != ' ') && row[0][9] == row[1][9] && row[1][9] == row[2][9])
 {
printf("da f");
 return 1;
 }                      //compaire every column


 else if((row[0][9] != ' ') && row[0][9] == row[1][5] && row[1][5] == row[2][1])
 {
return 1;
 }
 else if((row[0][1] != ' ') && row[0][1] == row[1][5] && row[1][5] == row[2][9])
 {
return 1;
 }

 else
 {
 return 0;
 }


}



char *prompt()
{
   int cur_array_len = 2;
   int pos = 0;
   char ch;
   char *text = NULL;
   text = malloc(sizeof(char) * cur_array_len);
   do
   {
      scanf("%c", &ch);
      if(ch == '\n')
      {
     text[pos] = '\0';
      }
      else
      {
     text[pos] = ch;
     pos++;
     if(pos == cur_array_len - 1)
     {
        // expand array
        char *t2 = malloc(sizeof(char) * cur_array_len * 2);
        int i;
        for(i = 0; i < cur_array_len; i++)
        {
           t2[i] = text[i];
        }
        cur_array_len *= 2;
        free(text);
        text = t2;
     }
      }
   } while(ch != '\n');
   return text;
}
大概就是X,O两人轮流下棋。若先有一方棋子练成线则赢,输入大写Q则对家赢,其它情况提示有误并且让用户重新输入。每方棋子只有三颗,所以前三轮是“新添”棋子,之后要靠“移动,”现在我只是在完成“新添”部分,可是用户在比如printf(“player X: ”)用户直接输入回车的话就怎么也不行,想请教如何解决这个问题!
如果用户输入的既有数字也有字符怎么办?
 
0

回复列表 (共2个回复)

沙发

中国台湾

板凳

在线博彩平台:www.pb258.com
在线博彩平台:www.jjxtech.com 
在线博彩平台:www.lcmty.com 
在线博彩平台:www.7macau.com
在线博彩平台:www.7macau.net
在线博彩平台:www.bp258.com
在线博彩平台:www.258bp.com

我来回复

您尚未登录,请登录后再回复。点此登录或注册