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主题:给你们出一道qb希望你们能答对三天后给通过信箱给你们答案你们知道答案发在我的信箱内,

qirend@eyou.com[b]qirend@eyou.com[/b]
[center]qirend@eyou.com[/center]
declare sub ss(m as integer, n as integer)
dim shared a as integer
dim b as integer
a =10:b=10
call ss (a,b)
print "a=";a,"b=";b
a=20:b=20
call ss ((a),b)
print "a=";a,"b=";b
end
sub ss (m,n)
static c
n=n+c+m
c=a
end sub

[fly]dim shared a as integer[/fly][size=6]dim shared a as integer[/size][color=000080]dim shared a as integer[/color][font=黑体]dim shared a as integer[/font]

回复列表 (共3个回复)

沙发

各位同胞,兄弟姐妹,给点掌声好不好,虽然我的QB不怎么好,但我也是你们当中的一员,各位,不知你们的AB 学得怎么样,是不是和我一样,QB 是很好学的,希望各位多多努力才行呀,好,就说这些

板凳

这还不简单?
这里的人还有哪个是没有QB的?
放进去运行一下还不知道?

我比较笨,不懂,只好胡猜一通喔。
10,20
20,50

3 楼

拜托程序贴上来之前现运行一下,然后以标准形式贴出来
DECLARE SUB ss (m AS INTEGER, n AS INTEGER)
DIM SHARED a AS INTEGER
DIM b AS INTEGER

a = 10: b = 10: CALL ss(a, b)
PRINT "a="; a, "b="; b

a = 20: b = 20: CALL ss((a), b)
PRINT "a="; a, "b="; b
END

SUB ss (m AS INTEGER, n AS INTEGER)
   STATIC c
   n = n + c + m
   c = a
END SUB

运行后显示如下:
a= 10         b= 20
a= 20         b= 50

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