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lws
[专家分：0] 发布于 2005-10-08 14:33:00
void __fastcall TForm1::Button3Click(TObject *Sender)
{
if(OpenDialog2->Execute()==true)
ficfile=OpenDialog2->FileName;
else
return;
Button4->Enabled=true;
}
问题是:
[C++ Error] Unit1.cpp(568): E2089 Identifier 'Button3Click' cannot have a type qualifier
请高手指点.谢谢.
{
if(OpenDialog2->Execute()==true)
ficfile=OpenDialog2->FileName;
else
return;
Button4->Enabled=true;
}
问题是:
[C++ Error] Unit1.cpp(568): E2089 Identifier 'Button3Click' cannot have a type qualifier
请高手指点.谢谢.
