您所在位置：主题：jsp 连接sql2000出现问题
一天12
[专家分：0] 发布于 2007-03-20 14:59:00
<%@ page contentType="text/html;charset=GB2312" %>
<%@page import="java.sql.*"%>
<html>
<body>
<%Class.forName("com.microsoft.jdbc.sqlserver.SQLServerDriver").newInstance();
string url="jdbc:microsoft:sqlserver://localhost:1433;DatabaseName=finger";
String user="sa";
String password="sa";
Connection conn= DriverManager.getConnection(url,user,password);
Statement stmt=conn.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_UPDATABLE);
String sql="select * from student";
ResultSet rs=stmt.executeQuery(sql);
while(rs.next()){% >
您的第一个字段内容为： <%=rs.getString(1)%>
您的第二个字段内容为： <%=rs.getString(2)%>
<%}%>
<%out.print("数据库操作成功，恭喜 ");%>
<%rs.close();
stmt.close();
conn.close();
%>
</body>
</html>
用的是网上下的例子，系统是xp，sql2000已经打上sp4的补丁，但还是出项了错误如下：
HTTP Status 500 -
--------------------------------------------------------------------------------
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 5 in the jsp file: /testsql.jsp
Generated servlet error:
Syntax error on tokens, Expression expected instead
An error occurred at line: 5 in the jsp file: /testsql.jsp
Generated servlet error:
Syntax error, insert ";" to complete BlockStatements
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:512)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:377)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 5 in the jsp file: /testsql.jsp
Generated servlet error:
Syntax error on tokens, Expression expected instead
An error occurred at line: 5 in the jsp file: /testsql.jsp
Generated servlet error:
Syntax error, insert ";" to complete BlockStatements
org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:84)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:328)
org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:414)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:297)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:276)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:264)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:563)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:305)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
note The full stack trace of the root cause is available in the Apache Tomcat/5.5.20 logs.
请各位看看是哪里的错误？[em18]
<%@page import="java.sql.*"%>
<html>
<body>
<%Class.forName("com.microsoft.jdbc.sqlserver.SQLServerDriver").newInstance();
string url="jdbc:microsoft:sqlserver://localhost:1433;DatabaseName=finger";
String user="sa";
String password="sa";
Connection conn= DriverManager.getConnection(url,user,password);
Statement stmt=conn.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_UPDATABLE);
String sql="select * from student";
ResultSet rs=stmt.executeQuery(sql);
while(rs.next()){% >
您的第一个字段内容为： <%=rs.getString(1)%>
您的第二个字段内容为： <%=rs.getString(2)%>
<%}%>
<%out.print("数据库操作成功，恭喜 ");%>
<%rs.close();
stmt.close();
conn.close();
%>
</body>
</html>
用的是网上下的例子，系统是xp，sql2000已经打上sp4的补丁，但还是出项了错误如下：
HTTP Status 500 -
--------------------------------------------------------------------------------
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 5 in the jsp file: /testsql.jsp
Generated servlet error:
Syntax error on tokens, Expression expected instead
An error occurred at line: 5 in the jsp file: /testsql.jsp
Generated servlet error:
Syntax error, insert ";" to complete BlockStatements
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:512)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:377)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 5 in the jsp file: /testsql.jsp
Generated servlet error:
Syntax error on tokens, Expression expected instead
An error occurred at line: 5 in the jsp file: /testsql.jsp
Generated servlet error:
Syntax error, insert ";" to complete BlockStatements
org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:84)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:328)
org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:414)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:297)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:276)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:264)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:563)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:305)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
note The full stack trace of the root cause is available in the Apache Tomcat/5.5.20 logs.
请各位看看是哪里的错误？[em18]