主题:[讨论]歌德巴赫猜想
bond007
[专家分:130] 发布于 2007-08-06 21:13:00
给程序!!!
回复列表 (共7个回复)
沙发
wzc1996 [专家分:1680] 发布于 2007-08-06 21:17:00
CLS
DO
INPUT N
LOOP UTNIL N>6
K=2
DO WHILE K<N
K=K+1
F= -1
FOR I=2 TO INT(SQR(K))
IF K MOD I=0 THEN F=0
NEXT I
D=N-K
IF D>1 AND F=-1 THEN
F1=-1
FOR I=2 TO INT(SQR(D))
IF D MOD I=0 THEN F1=0
NEXT I
IF F1=-1 THEN PRINT N;"=";K;"+";"D";:END IF
END IF
LOOP
板凳
Matodied [专家分:7560] 发布于 2007-08-06 21:28:00
楼上简直是错误百出,你还给他加30分!
看我的!
DECLARE FUNCTION isprime! (m!)
CLS
1 INPUT n
IF n MOD 2 = 1 OR n <> INT(n) OR n < 4 THEN 1
FOR i = 2 TO n \ 2
j = n - i
IF isprime(i) THEN
IF isprime(j) THEN PRINT n; "="; i; "+"; j; : END
END IF
NEXT i
END
FUNCTION isprime (m)
FOR i = 2 TO INT(SQR(m))
IF m MOD i = 0 THEN isprime = 0: EXIT FUNCTION
NEXT i
isprime = 1
END FUNCTION
3 楼
为谁疯狂 [专家分:0] 发布于 2009-09-08 23:34:00
我也来凑热闹
1:input n
if n<6 or n mod 2 <> 0 or n <> int(n) then goto 1
for i=1 to n/2
a=i
b=n-i
c=a
gosub 10
if flag =1 then goto 20
c=b
gosub 10
if flag =0 then print a;"+";b;"=";c;
20:
next i
end
10
flag =0
for j=2 to int(sqr(c))
if c mod j = 0 then flag =1
next j
return
4 楼
phile [专家分:2310] 发布于 2009-09-10 17:34:00
1楼是错误多
应是
CLS
DO
INPUT N
LOOP UNTIL N > 6 AND N MOD 2 = 0 AND INT(N) = N
K = 2
DO WHILE K < N \ 2
K = K + 1
F = -1
FOR I = 2 TO INT(SQR(K))
IF K MOD I = 0 THEN F = 0
NEXT I
D = N - K
IF D > 1 AND F = -1 THEN
F1 = -1
FOR I = 2 TO INT(SQR(D))
IF D MOD I = 0 THEN F1 = 0
NEXT I
IF F1 = -1 THEN PRINT N; "="; K; "+"; D
END IF
LOOP
5 楼
天天和和 [专家分:1420] 发布于 2009-09-12 13:52:00
嗯嗯 不错不错
这可是一个 老帖子 啊
6 楼
phile [专家分:2310] 发布于 2009-09-13 09:33:00
老?
7 楼
zihao1231 [专家分:150] 发布于 2009-11-21 20:29:00
CLS
DO
INPUT N
LOOP UNTIL N>4
FOR I = N\2 TO 1 STEP -1
A=I
B=N-A
GOSUB 10
NEXT I
END
10
F=0
FOR J = 2 TO INT(SQR(A))
IF A MOD J = 0 THEN F=1:EXIT FOR
NEXT J
IF F=1 THEN RETURN
F=0
FOR J = 2 TO INT(SQR(B))
IF B MOD J = 0 THEN F=1:EXIT FOR
NEXT J
IF F=0 THEN ?A;B:END ELSE RETURN
我来回复