在下面代码中，当一个进程执行wait语句时有个进程执行notifyAll语句，那么被唤醒的进程是从那一句开始执行呢？      
        //以下是P原语
    public static synchronized  void P(int semaphore){
        semaphore--;
        if(semaphore<0){
        try{
            Ph.class.wait();
        }catch(InterruptedException e){} }
    }
    //以下是V原语
    public  static synchronized void V(int semaphore){
        semaphore++;
        Ph.class.notifyAll();
} 
整个类如下：
class Philosopher extends Thread{
    static int mutex=2;
    static int[] Chopstick={1,1,1,1,1};
    private int number;
    public Philosopher(int num){
        number=num;
        start();
    }
    public String toString(){
        return "Philosopher"+number;
    }//以下是P原语
    public static synchronized  void P(int semaphore){
        semaphore--;
        if(semaphore<0){
        try{
            Philosopher.class.wait();
        }catch(InterruptedException e){} }
    }//以下是V原语
    public  static synchronized void V(int semaphore){
        semaphore++;
        Philosopher.class.notify();
} 

    public void think(){
        System.out.println(this+" is thinking");
        
        try{
            sleep((int)(50*Math.random()));
        }
        catch(InterruptedException e){
                //throw new RuntimeException(e);
                }
        
    }
    public void eat(){
    P(mutex);
        P(Chopstick[(number+1)%5]);
        //为简写代码，默认取筷子的顺序是相同的，都是先取右边
        System.out.println(this+"拿到右边的筷子等待左边的筷子");
        try{
            Thread.sleep(10);
            }catch(InterruptedException e){}
        P(Chopstick[(number)%5]);
        System.out.println(this+"拿到两边的筷子，正在进餐");
    //V(mutex);
        V(Chopstick[(number+1)%5]);
        V(Chopstick[(number)%5]);
     V(mutex);
    }
    public void run()
    {
        while(true)
        {
            think();
            eat();
            }
        }
    
}