主题:VB图片翻转并保存程序出错,哪位高手帮帮忙,问题出在哪里?谢谢!
Private Sub Command1_Click()
Picture2.Cls
Picture2.Picture = LoadPicture("")
Picture2.PaintPicture Picture1.Picture, Picture1.ScaleWidth, 0, -Picture1.ScaleWidth
SavePicture Picture2.Picture, "c:\MyPicture.bmp"
End Sub
上面的程序(VB)用两个PICTUREBOX PICTURE1和PICTURE1翻转图片并保存时在
SavePicture Picture2.Picture, "c:\MyPicture.bmp"
上出现“无效属性值”错误,问题出在哪里?
哪位高手帮我看一下,怎样才能解决?
特别急用,谢谢!
Picture2.Cls
Picture2.Picture = LoadPicture("")
Picture2.PaintPicture Picture1.Picture, Picture1.ScaleWidth, 0, -Picture1.ScaleWidth
SavePicture Picture2.Picture, "c:\MyPicture.bmp"
End Sub
上面的程序(VB)用两个PICTUREBOX PICTURE1和PICTURE1翻转图片并保存时在
SavePicture Picture2.Picture, "c:\MyPicture.bmp"
上出现“无效属性值”错误,问题出在哪里?
哪位高手帮我看一下,怎样才能解决?
特别急用,谢谢!