您所在位置：主题：Arc()函数问题
kamen222
[专家分：0] 发布于 2008-01-21 16:21:00
for(i=3;i<6;i++)
{
pDC->Arc(260-10*i,70-10*i,260+10*i,70+10*i,
(int)260+10*i*cos(60*3.1415926/180),
(int)70+10*i*sin(60*3.1415926/180),
(int)260+10*i*cos(60*3.1415926/180),
(int)70-10*i*sin(60*3.1415926/180));
pDC->Arc(260-10*i,70-10*i,260+10*i,70+10*i,
(int)260-10*i*cos(60*3.1415926/180),
(int)70-10*i*sin(60*3.1415926/180),
(int)260-10*i*cos(60*3.1415926/180),
(int)70+10*i*sin(60*3.1415926/180));
这个画弧程序中cos(60*3.1415926/180)是什么意思？弧线函数原型中后四个参数不是弧线的始点坐标和终点坐标吗。
{
pDC->Arc(260-10*i,70-10*i,260+10*i,70+10*i,
(int)260+10*i*cos(60*3.1415926/180),
(int)70+10*i*sin(60*3.1415926/180),
(int)260+10*i*cos(60*3.1415926/180),
(int)70-10*i*sin(60*3.1415926/180));
pDC->Arc(260-10*i,70-10*i,260+10*i,70+10*i,
(int)260-10*i*cos(60*3.1415926/180),
(int)70-10*i*sin(60*3.1415926/180),
(int)260-10*i*cos(60*3.1415926/180),
(int)70+10*i*sin(60*3.1415926/180));
这个画弧程序中cos(60*3.1415926/180)是什么意思？弧线函数原型中后四个参数不是弧线的始点坐标和终点坐标吗。
